MHT CET · Maths · Differential Equations
The micro-organisms double themselves in 3 hours. Assuming that the quantity increases at a rate proportional to it self, then the number of times it multiplies themselves in 18 years is
- A 32
- B 64
- C 128
- D 40
Answer & Solution
Correct Answer
(B) 64
Step-by-step Solution
Detailed explanation
(B)
Let initial number of microorganisms be \(\mathrm{N}\). The microorganisms double themselves in 3 hours. \(\therefore\) Number of microorganisms after
3 hours \(=2 \times \mathrm{N}=2 \mathrm{~N}\)
o hours \(=2 \times 2 \mathrm{~N}=4 \mathrm{~N}\)
9 hours \(=2 \times 4 \mathrm{~N}=8 \mathrm{~N}\)
12 hours \(=2 \times 8 \mathrm{~N}=16 \mathrm{~N}\)
15 hours \(=2 \times 16 \mathrm{~N}=32 \mathrm{~N}\)
18 hours \(=2 \times 32 \mathrm{~N}=64 \mathrm{~N}\)
Let initial number of microorganisms be \(\mathrm{N}\). The microorganisms double themselves in 3 hours. \(\therefore\) Number of microorganisms after
3 hours \(=2 \times \mathrm{N}=2 \mathrm{~N}\)
o hours \(=2 \times 2 \mathrm{~N}=4 \mathrm{~N}\)
9 hours \(=2 \times 4 \mathrm{~N}=8 \mathrm{~N}\)
12 hours \(=2 \times 8 \mathrm{~N}=16 \mathrm{~N}\)
15 hours \(=2 \times 16 \mathrm{~N}=32 \mathrm{~N}\)
18 hours \(=2 \times 32 \mathrm{~N}=64 \mathrm{~N}\)
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