MHT CET · Maths · Linear Programming
The maximum value of \(z=9 x+13 y\) subject to \(2 x+3 y \leq 18,2 x+y \leq 10, x \geq 0, y \geq 0\) is
- A 130
- B 81
- C 79
- D 99
Answer & Solution
Correct Answer
(C) 79
Step-by-step Solution
Detailed explanation
The feasible region is \(O A B C\).
\(\begin{array}{ll}\text { At } & A(5,0), z=45 \\ \text { At } & B(3,4), z=27+52=79\end{array}\)
At \(\quad C(0,6), z=78\)
\(\therefore\) Maximum value of \(z\) is 79 .
\(\begin{array}{ll}\text { At } & A(5,0), z=45 \\ \text { At } & B(3,4), z=27+52=79\end{array}\)
At \(\quad C(0,6), z=78\)
\(\therefore\) Maximum value of \(z\) is 79 .
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