MHT CET · Maths · Linear Programming
The maximum value of \(z=50 x+15 y\) subject to the constraints \(x+y \leq 60 ; 5 x+y \leq 100 ; x \geq 0 ; y \geq 0\) is at the point
- A \(2650,(50,10)\)
- B \(1000,(20,0)\)
- C \(900,(0,60)\)
- D \(1250,(10,50)\)
Answer & Solution
Correct Answer
(D) \(1250,(10,50)\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Z}_{\text {max. }}\) at \((10,50)\)
\(\begin{aligned} & Z_{\text {max. }}=50 \times 10+15 \times 50 \\ & =500+750 \\ & =1250\end{aligned}\)
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