MHT CET · Maths · Linear Programming
The maximum value of the objective function \(\mathrm{z}=2 \mathrm{x}+3 \mathrm{y}\) subject to the constraints \(\mathrm{x}+\mathrm{y} \leq 5,2 \mathrm{x}+\mathrm{y} \geq 4\) and \(\mathrm{x} \geq 0, \mathrm{y} \geq 0\) is
- A 15
- B 10
- C 20
- D 25
Answer & Solution
Correct Answer
(A) 15
Step-by-step Solution
Detailed explanation
Refer Figure

Required part is shaded.
We have \(\mathrm{A}=(0,4)\);
\(
\begin{aligned}
& \mathrm{B}=(2,0) ; \mathrm{C}=(5,0) \\
& \mathrm{D}=(0,5)
\end{aligned}
\)
We have to maximize function
\(
\begin{aligned}
\mathrm{Z}=2 \mathrm{x} & +3 \mathrm{y} \\
\therefore \quad \mathrm{z}_{\mathrm{A}} & =2(0)+3(4)=12 \\
\mathrm{Z}_{\mathrm{B}} & =2(2)+3(0)=4 \\
\mathrm{Z}_{\mathrm{C}} & =2(5)+3(0)=10 \\
\mathrm{Z}_{\mathrm{D}} & =2(0)+3(5)=15
\end{aligned}
\)

Required part is shaded.
We have \(\mathrm{A}=(0,4)\);
\(
\begin{aligned}
& \mathrm{B}=(2,0) ; \mathrm{C}=(5,0) \\
& \mathrm{D}=(0,5)
\end{aligned}
\)
We have to maximize function
\(
\begin{aligned}
\mathrm{Z}=2 \mathrm{x} & +3 \mathrm{y} \\
\therefore \quad \mathrm{z}_{\mathrm{A}} & =2(0)+3(4)=12 \\
\mathrm{Z}_{\mathrm{B}} & =2(2)+3(0)=4 \\
\mathrm{Z}_{\mathrm{C}} & =2(5)+3(0)=10 \\
\mathrm{Z}_{\mathrm{D}} & =2(0)+3(5)=15
\end{aligned}
\)
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