MHT CET · Maths · Trigonometric Ratios & Identities
\(\quad\) The maximum value of the function \(y=e^{5+\sqrt{3} \sin x+\cos x}\) is
- A \(e^{7}\)
- B \(e^{2}\)
- C \(e^{5}\)
- D \(e^{8}\)
Answer & Solution
Correct Answer
(A) \(e^{7}\)
Step-by-step Solution
Detailed explanation
Maximum value of \(\sqrt{3} \sin x+\cos x\) is \(\sqrt{(\sqrt{3})^{2}+(1)^{2}}=2\)
Hence maximum value of given function is \(\mathrm{e}^{5+2}=\mathrm{e}^{7}\)
Hence maximum value of given function is \(\mathrm{e}^{5+2}=\mathrm{e}^{7}\)
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