MHT CET · Maths · Vector Algebra
The maximum value and minimum value of the volume of the parallelopiped having coterminous edges \(\hat{i}+x \hat{j}+\hat{\mathrm{k}}, \hat{\mathrm{j}}+x \hat{\mathrm{k}}\) and \(x \hat{i}+\hat{\mathrm{k}}\) are respectively
- A \(\frac{1}{3 \sqrt{3}}+1, \frac{-1}{3 \sqrt{3}}+1\)
- B \(\frac{2}{3 \sqrt{3}}+1, \frac{-2}{3 \sqrt{3}}+1\)
- C \(\frac{1}{\sqrt{3}}+1, \frac{-1}{\sqrt{3}}+1\)
- D \(\frac{2}{\sqrt{3}}+1, \frac{-2}{\sqrt{3}}+1\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{3 \sqrt{3}}+1, \frac{-2}{3 \sqrt{3}}+1\)
Step-by-step Solution
Detailed explanation
Let the edges be \( \vec{a} = \hat{i}+x \hat{j}+\hat{\mathrm{k}} \), \( \vec{b} = \hat{\mathrm{j}}+x \hat{\mathrm{k}} \), and \( \vec{c} = x \hat{i}+\hat{\mathrm{k}} \). The volume of the parallelopiped is \( V = |\vec{a} \cdot (\vec{b} \times \vec{c})| = \left| \det \begin{pmatrix} 1 & x & 1 \\ 0 & 1 & x \\ x & 0 & 1 \end{pmatrix} \right| \).
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