MHT CET · Maths · Three Dimensional Geometry
The magnitude of the projection of the vector \(2 \hat{i}+3 \hat{j}+\hat{k}\) on the vector perpendicular to the plane containing the vectors \(\hat{i}+\hat{j}+\hat{k}\) and \(\hat{i}+2 \hat{j}+3 \hat{k}\) is
- A \(\sqrt{\frac{3}{2}}\) units
- B \(\frac{\sqrt{3}}{2}\) units
- C \(\frac{3}{\sqrt{2}}\) units
- D \(3 \sqrt{6}\) units
Answer & Solution
Correct Answer
(A) \(\sqrt{\frac{3}{2}}\) units
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{|(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot\{(\hat{i}+\hat{j}+\hat{k}) \times(\hat{i}+2 \hat{j}+3 \hat{k})\}|}{|(\hat{i}+\hat{j}+\hat{k}) \times(\hat{i}+2 \hat{j}+3 \hat{k})|} \\ & =\frac{|(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot(\hat{i}-2 \hat{j}+\hat{k})|}{|\hat{i}+\hat{j}+\hat{k}|} \\ & =\frac{|2-6+1|}{\sqrt{1^2+(-2)^2+1^2}}=\frac{3}{\sqrt{6}}=\sqrt{\frac{3}{2}}\end{aligned}\)
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