MHT CET · Maths · Mathematical Reasoning
The logical statement \((\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{p} \rightarrow \sim \mathrm{p})\) is equivalent to
- A \(\sim \mathrm{p}\)
- B \(\mathrm{p}\)
- C \(q\)
- D \(\sim q\)
Answer & Solution
Correct Answer
(A) \(\sim \mathrm{p}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & (\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{q} \rightarrow \sim \mathrm{p}) \\ & \equiv(\sim \mathrm{p} \vee \mathrm{q}) \wedge(\sim \mathrm{q} \vee \sim \mathrm{p}) \\ & =(\sim \mathrm{p}) \vee(\mathrm{q} \wedge-\mathrm{q}) \\ & \equiv(\sim \mathrm{p}) \vee \mathrm{F} \equiv \sim \mathrm{p}\end{aligned}\)
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