MHT CET · Maths · Three Dimensional Geometry
The lines \(\frac{\mathrm{x}-3}{1}=\frac{\mathrm{y}-2}{1}=\frac{\mathrm{z}-5}{-\mathrm{k}}\) and \(\frac{\mathrm{x}-4}{\mathrm{k}}=\frac{\mathrm{y}-3}{1}=\frac{\mathrm{z}-3}{2}\) are coplanar, hence \(\mathrm{k}=\)
- A 1,2
- B \(-2,3\)
- C \(-1,2\)
- D \(\frac{1}{2}, 1\)
Answer & Solution
Correct Answer
(A) 1,2
Step-by-step Solution
Detailed explanation
\(A(3, 2, 5)\), \(\vec{v_1} = \langle 1, 1, -k \rangle\) \(B(4, 3, 3)\), \(\vec{v_2} = \langle k, 1, 2 \rangle\)
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