MHT CET · Maths · Determinants
The lines \(x+2 a y+a=0, x+3 b y+b=0, x+4 c y+c=0\) are concurrent then \(a, \mathrm{~b}, \mathrm{c}\) are in
- A Harmonic progression
- B Geometric progression
- C Arithmetic progression
- D Arithmetico geometric progression
Answer & Solution
Correct Answer
(A) Harmonic progression
Step-by-step Solution
Detailed explanation
\(\begin{vmatrix} 1 & 2a & a \\ 1 & 3b & b \\ 1 & 4c & c \end{vmatrix} = 0\) \(1(3bc-4bc) - 2a(c-b) + a(4c-3b) = 0\)
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