MHT CET · Maths · Three Dimensional Geometry
The lines \(\frac{x-0}{1}=\frac{y-2}{2}=\frac{z+3}{\lambda}\) and \(\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{\lambda}\) are coplanar and \(p\) is the plane containing these lines, then which of following point lie on the plane for all values of (\(\lambda\)).
- A \((1,6,4)\)
- B \((2,8,7)\)
- C \((1,2,3)\)
- D \((4,10,9)\)
Answer & Solution
Correct Answer
(D) \((4,10,9)\)
Step-by-step Solution
Detailed explanation
\(\vec{P_1}(0, 2, -3)\), \(\vec{d_1}=(1, 2, \lambda)\) \(\vec{P_2}(2, 6, 3)\), \(\vec{d_2}=(2, 3, \lambda)\)
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