MHT CET · Maths · Three Dimensional Geometry
The line passing through the points \((a, 1,6)\) and \((3,4, b)\) crosses the yz -plane at \(\left(0, \frac{17}{2}, \frac{-13}{2}\right)\), then the value of \((3 a+4 b)\) is
- A 19
- B 16
- C 21
- D 23
Answer & Solution
Correct Answer
(A) 19
Step-by-step Solution
Detailed explanation
\(k = \frac{y_3 - y_1}{y_2 - y_1}\) \(k = \frac{\frac{17}{2} - 1}{4 - 1} = \frac{\frac{15}{2}}{3} = \frac{5}{2}\)
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