MHT CET · Maths · Three Dimensional Geometry
The line \(L\) is passing through \((1,2,3)\). The distance of any point on the line \(L\) from the line \(\bar{r}=(3 \lambda-1) \hat{i}+(-2 \lambda+3) \hat{j}+(4+\lambda) \hat{k}\) is constant. Then the line \(L\) does not pass through the point
- A \((4,0,4)\)
- B \((-2,4,2)\)
- C \((7,-2,5)\)
- D \((-5,6,2)\)
Answer & Solution
Correct Answer
(D) \((-5,6,2)\)
Step-by-step Solution
Detailed explanation
The line \(\bar{r}=(3 \lambda-1) \hat{i}+(-2 \lambda+3) \hat{j}+(4+\lambda) \hat{k}\) passes through \((-1,3,4)\) and has direction vector \(\vec{d_1}=(3,-2,1)\). If the distance of any point on line \(L\) from this line is constant, then line \(L\) must be parallel to \(\vec{d_1}\).
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