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MHT CET · Maths · Three Dimensional Geometry

The line drawn \((4,-1,2)\) and \((-3,2,3)\) meets the plane at right angles at the point \((-10,5,4)\) then the equation of plane is

  1. A \(2 x-y-z+29=0\)
  2. B \(7 x-3 y-z+89=0\)
  3. C \(x-y+z+11=0\)
  4. D \(x+y+z+1=0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7 x-3 y-z+89=0\)

Step-by-step Solution

Detailed explanation

d.r's of normal to the plane are \( < 4-(-3),-1-2\), \(2-3>^0 < 7,-3,-1>\)
and it passes through \((-10,5,4)\). Hence the required equation is
\(\begin{aligned}
& 7(x-(-10))-3(y-5)-1(z-4)=0 \\
& \Rightarrow 7 x-3 y-z+89=0
\end{aligned}\)