MHT CET · Maths · Application of Derivatives
The length of the perpendicular drawn from the origin on the normal to the curve \(x^2+2 x y-3 y^2=0\) at the point \((2,2)\) is
- A \(\sqrt{2}\) units
- B \(3 \sqrt{2}\) units
- C \(2 \sqrt{2}\) units
- D \(\frac{1}{\sqrt{2}}\) units
Answer & Solution
Correct Answer
(C) \(2 \sqrt{2}\) units
Step-by-step Solution
Detailed explanation
Curve: \(x^2+2 x y-3 y^2=0\) Differentiating w.r.t. \(x\): \(2x + 2(y + x\frac{dy}{dx}) - 6y\frac{dy}{dx} = 0\)
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