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MHT CET · Maths · Three Dimensional Geometry

The length of the foot of the perpendicular from the point \(\left(1, \frac{3}{2}, 2\right)\) to the plane \(2 x-2 y+4 z+17=0\) is

  1. A \(\sqrt{6}\) units
  2. B \(3 \sqrt{3}\) units
  3. C \(4 \sqrt{3}\) units
  4. D \(2 \sqrt{6}\) units
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \sqrt{6}\) units

Step-by-step Solution

Detailed explanation

\(d = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}}\) \(d = \frac{|2(1) - 2\left(\frac{3}{2}\right) + 4(2) + 17|}{\sqrt{2^2 + (-2)^2 + 4^2}}\)