MHT CET · Maths · Limits
The left-hand derivative of \(\mathrm{f}(x)=[x] \sin (\pi x)\), at \(x=\mathrm{k}, \mathrm{k}\) is an integer and \([\cdot]\) is the greatest integer function, is
- A \((-1)^{\mathrm{k}}(\mathrm{k}-1) \pi\)
- B \((-1)^{\mathrm{k}-1}(\mathrm{k}-1) \pi\)
- C \((-1)^{\mathrm{k}} \mathrm{k} \pi\)
- D \((-1)^{\mathrm{k}-1} \mathrm{k} \pi\)
Answer & Solution
Correct Answer
(A) \((-1)^{\mathrm{k}}(\mathrm{k}-1) \pi\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} f(x)= & {[x] \sin (\pi x) } \\ \text { LHD } & =\lim _{h \rightarrow 0} \frac{f(k-h)-f(k)}{-h} \\ & =\lim _{h \rightarrow 0} \frac{[k-h] \sin \pi(k-h)-[k] \sin k \pi}{-h} \\ & =\lim _{h \rightarrow 0} \frac{(k-1) \sin (k \pi-\pi h)-k \sin k \pi}{-h} \\ & =\lim _{h \rightarrow 0} \frac{(-1)^{k+1}(k-1) \sinh \pi-0}{-h} \quad \ldots[\because k \in I] \\ & =(-1)^k(k-1) \pi\end{aligned}\)
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