MHT CET · Maths · Pair of Lines
The joint equation of the bisector of the angle between the lines \(2 x^2+11 x y+3 y^2=0\) is
- A \(11 x^2+2 x y-11 y^2=0\)
- B \(x^2+2 x y-y^2=0\)
- C \(3 x^2-11 x y+2 y^2=0\)
- D \(11 x^2-2 x y-11 y^2=0\)
Answer & Solution
Correct Answer
(A) \(11 x^2+2 x y-11 y^2=0\)
Step-by-step Solution
Detailed explanation
\(a = 2, 2h = 11 \Rightarrow h = \frac{11}{2}, b = 3\) \( \frac{x^2 - y^2}{a - b} = \frac{xy}{h} \)
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