MHT CET · Maths · Differential Equations
The integrating factor of the differential equation \(\frac{d y}{d x}(x \log x)+y=2 \log x\) is given by
- A \(e^{x}\)
- B \(\log x\)
- C \(\log (\log x)\)
- D \(x\)
Answer & Solution
Correct Answer
(B) \(\log x\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{d y}{d x}(x \log x)+y=2 \log x \\ & \Rightarrow \frac{d y}{d x}+\frac{y}{x \log x}=\frac{2}{x} \end{aligned}\)
Here, \(\quad P=\frac{1}{x \log x}, Q=\frac{2}{x}\)
IF
\(
=e^{\int P d x}=e^{\int \frac{d x}{x \log x}}
\)
\(=\log x\)
Here, \(\quad P=\frac{1}{x \log x}, Q=\frac{2}{x}\)
IF
\(
=e^{\int P d x}=e^{\int \frac{d x}{x \log x}}
\)
\(=\log x\)
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