MHT CET · Maths · Permutation Combination
The greatest possible number of points of intersection of 8 distinct straight lines and 4 distinct circles is
- A \(28\)
- B \(104\)
- C \({ }^{12} \mathrm{C}_2\)
- D \({ }^4 C_2\)
Answer & Solution
Correct Answer
(B) \(104\)
Step-by-step Solution
Detailed explanation
Lines intersecting lines: \( \frac{8 \times 7}{2} = 28 \) Circles intersecting circles: \( \frac{4 \times 3}{2} \times 2 = 12 \)
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