MHT CET · Maths · Trigonometric Equations
The general solutions of the equation \(\tan ^2 \theta+\sec 2 \theta=1\) are
- A \(n \pi, n \pi \pm \frac{\pi}{3}, n \in \mathbb{Z}\)
- B \(n \pi, n \pi \pm \frac{\pi}{4}, n \in \mathbb{Z}\)
- C \(\frac{n \pi}{4}, \frac{n \pi}{4} \pm \frac{\pi}{3}, n \in \mathbb{Z}\)
- D \(\mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{6}, \mathrm{n} \in \mathbb{Z}\)
Answer & Solution
Correct Answer
(A) \(n \pi, n \pi \pm \frac{\pi}{3}, n \in \mathbb{Z}\)
Step-by-step Solution
Detailed explanation
\(\tan ^2 \theta+\frac{1+\tan^2\theta}{1-\tan^2\theta}=1\) Let \(x = \tan^2\theta\): \(x+\frac{1+x}{1-x}=1\)
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