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MHT CET · Maths · Differential Equations

The general solution of the differential equation \(\frac{d y}{d x}+\frac{1}{\sqrt{1-x^{2}}}=0\) is

  1. A \(y^{2}+2 \sin ^{-1} x=c\)
  2. B \(x+\sin ^{-1} y=c\)
  3. C \(y+\sin ^{-1} x=c\)
  4. D \(x^{2}+2 \sin ^{2} y=c\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(y+\sin ^{-1} x=c\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}+\frac{1}{\sqrt{1-x^{2}}}=0\)
\(\therefore \frac{d y}{d x}=\frac{-1}{\sqrt{1-x^{2}}} \Rightarrow d y=\frac{-d x}{\sqrt{1-x^{2}}} \Rightarrow \int d y=-\int \frac{d x}{\sqrt{1-x^{2}}}\)
\(\therefore y=-\sin ^{-1} x+c\)