MHT CET · Maths · Differential Equations
The general solution of the differential equation \(\frac{d y}{d x}+\frac{1}{\sqrt{1-x^{2}}}=0\) is
- A \(y^{2}+2 \sin ^{-1} x=c\)
- B \(x+\sin ^{-1} y=c\)
- C \(y+\sin ^{-1} x=c\)
- D \(x^{2}+2 \sin ^{2} y=c\)
Answer & Solution
Correct Answer
(C) \(y+\sin ^{-1} x=c\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}+\frac{1}{\sqrt{1-x^{2}}}=0\)
\(\therefore \frac{d y}{d x}=\frac{-1}{\sqrt{1-x^{2}}} \Rightarrow d y=\frac{-d x}{\sqrt{1-x^{2}}} \Rightarrow \int d y=-\int \frac{d x}{\sqrt{1-x^{2}}}\)
\(\therefore y=-\sin ^{-1} x+c\)
\(\therefore \frac{d y}{d x}=\frac{-1}{\sqrt{1-x^{2}}} \Rightarrow d y=\frac{-d x}{\sqrt{1-x^{2}}} \Rightarrow \int d y=-\int \frac{d x}{\sqrt{1-x^{2}}}\)
\(\therefore y=-\sin ^{-1} x+c\)
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