MHT CET · Maths · Application of Derivatives
The function \(\mathrm{f}(x)=[x(x-2)]^2\) is increasing in the set
- A \((-\infty, 0) \cup(2, \infty)\)
- B \((-\infty, 1)\)
- C \((1,2)\)
- D \((0,1) \cup(2, \infty)\)
Answer & Solution
Correct Answer
(D) \((0,1) \cup(2, \infty)\)
Step-by-step Solution
Detailed explanation
\(f(x) = (x^2-2x)^2\) \(f'(x) = 2(x^2-2x)(2x-2)\)
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