MHT CET · Maths · Application of Derivatives
The function \(\mathrm{f}(x)=x^3-6 x^2+a x+b\) satisfyies the conditions of Rolle's theorem in \([1,3]\). Then the values of \(a\) and \(b\) are respectively
- A \(11,-6\)
- B \(-6,11\)
- C \(-11,6\)
- D \(6, -11\)
Answer & Solution
Correct Answer
(A) \(11,-6\)
Step-by-step Solution
Detailed explanation
\(f(1) = f(3)\) \(1^3 - 6(1)^2 + a(1) + b = 3^3 - 6(3)^2 + a(3) + b\)
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