MHT CET · Maths · Three Dimensional Geometry
The foot of the perpendicular drawn from origin to a plane is \(\mathrm{M}(2,1,-2)\), then vector equation of the plane is
- A \(\bar{r} \cdot(2 \hat{i}+\hat{j}-2 \hat{k})=9\)
- B \(\overline{\mathrm{r}} \cdot(-2 \hat{\mathrm{i}}-\hat{\mathrm{j}}-2 \hat{\mathrm{k}})=7\)
- C \(\overline{\mathrm{r}} \cdot(2 \hat{\mathrm{i}}-\hat{\mathrm{j}}-2 \hat{\mathrm{k}})=9\)
- D \(\bar{r} \cdot(2 \hat{i}-\hat{j}-\hat{k})=7\)
Answer & Solution
Correct Answer
(A) \(\bar{r} \cdot(2 \hat{i}+\hat{j}-2 \hat{k})=9\)
Step-by-step Solution
Detailed explanation
The plane passes through \((2,1,-2)\)
This point satisfies the equation of plane in option (A).
Also, it has d.r.s. 2, 1, -2
\(\therefore \quad\) Option (A) is the correct answer.
This point satisfies the equation of plane in option (A).
Also, it has d.r.s. 2, 1, -2
\(\therefore \quad\) Option (A) is the correct answer.
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