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MHT CET · Maths · Probability

The following is the probability distribution of X
X 0 1 2 3
\(P(\mathrm{X}=x)\) \(\frac{1+\mathrm{p}}{5}\) \(\frac{2-2 \mathrm{p}}{5}\) \(\frac{2-\mathrm{p}}{5}\) \(\frac{2 \mathrm{p}}{5}\)

For a minimum value of p, the value of \(5 \mathrm{E}(\mathrm{X})\) is

  1. A \(5\)
  2. B \(6\)
  3. C \(7\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(6\)

Step-by-step Solution

Detailed explanation

\(P(\mathrm{X}=x) \ge 0 \Rightarrow \frac{1+\mathrm{p}}{5} \ge 0, \frac{2-2\mathrm{p}}{5} \ge 0, \frac{2-\mathrm{p}}{5} \ge 0, \frac{2\mathrm{p}}{5} \ge 0\) \(p \ge -1, p \le 1, p \le 2, p \ge 0 \Rightarrow 0 \le p \le 1\)
From MHT CET
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