MHT CET · Maths · Parabola
The focal distance of the point \((4,4)\) on the parabola with vertex at \(((0,0)\) and symmetric about y-axis is
- A 4
- B 5
- C \(5 \sqrt{2}\)
- D \(4 \sqrt{2}\)
Answer & Solution
Correct Answer
(B) 5
Step-by-step Solution
Detailed explanation
\(x^{2}=4 y\)
Focal distance = 5
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