MHT CET · Maths · Linear Programming
The feasible region of L. P. P.
Maximize \(\mathrm{z}=70 x+50 \mathrm{y}\) subject to \(8 x+5 y \leq 60,4 x+5 y \leq 40\) and \(x \geq 0, y \geq 0\)
is
- A a triangle
- B a square
- C a pentagon
- D a quadrilateral
Answer & Solution
Correct Answer
(D) a quadrilateral
Step-by-step Solution
Detailed explanation
| \(\text{line}\) | \(\text{Point on X- axis}\) | \(\text{Point on Y - axis}\) |
| \(8 x+5 y=60\) | \(\text{A} (7.5,0)\) | \(\text{B} (0,12)\) |
| \(4 x+5 y=40\) | \(\text{C} (10,0)\) | \(\text{D} (0,8)\) |
Point of intersection \(\mathrm{E} \equiv(5,4)\)
Also \(A=(7.5,0)\) and \(D \equiv(0,8)\)
So OAED is a quadrilateral.
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