MHT CET · Maths · Ellipse
The equations of two ellipses are be \(\frac{x^2}{4}+\frac{y^2}{2}=1\) and \(\frac{x^2}{36}+\frac{y^2}{b^2}=1\). If the product of their eccentricities is \(\frac{\sqrt{2}}{3}\), then the product of the length of the major axis and minor axis of the second ellipse is \(\qquad\)
- A \(12 \sqrt{5}\)
- B \(720\)
- C \(6 \sqrt{20}\)
- D \(48 \sqrt{5}\)
Answer & Solution
Correct Answer
(D) \(48 \sqrt{5}\)
Step-by-step Solution
Detailed explanation
\(e_1 = \sqrt{1 - \frac{2}{4}} = \frac{1}{\sqrt{2}}\) \(e_1 e_2 = \frac{\sqrt{2}}{3} \Rightarrow \frac{1}{\sqrt{2}} e_2 = \frac{\sqrt{2}}{3} \Rightarrow e_2 = \frac{2}{3}\)
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