ExamBro
ExamBro
MHT CET · Maths · Circle

The equations of the tangents to the circle \(x^2+y^2=36\) which are perpendicular to the line \(5 x+y=2\), are

  1. A \(x+5 y \pm 6 \sqrt{26}=0\)
  2. B \(x-5 y \pm 6 \sqrt{26}=0\)
  3. C \(5 x-y \pm 6 \sqrt{26}=0\)
  4. D \(5 x+y \pm 6 \sqrt{26}=0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x-5 y \pm 6 \sqrt{26}=0\)

Step-by-step Solution

Detailed explanation

\(r^2 = 36 \Rightarrow r=6\) Slope of \(5x+y=2\) is \(m_1 = -5\).