MHT CET · Maths · Circle
The equations of the tangents to the circle \(x^2+y^2=36\) which are perpendicular to the line \(5 x+y-2=0\) are
- A \(x-5 y \pm 6 \sqrt{26}=0\)
- B \(x+5 y \pm 6 \sqrt{26}=0\)
- C \(x-5 y \pm \sqrt{26}=0\)
- D \(x+5 y \pm \sqrt{26}=0\)
Answer & Solution
Correct Answer
(A) \(x-5 y \pm 6 \sqrt{26}=0\)
Step-by-step Solution
Detailed explanation
\(r = \sqrt{36} = 6\) Slope of given line \(m_1 = -5/1 = -5\)
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