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MHT CET · Maths · Application of Derivatives

The equation of the tangent to the curve \(y=b e^{-x / a}\) at the point where it crosses the Y axis is

  1. A \(x+\mathrm{y}=\mathrm{ab}\)
  2. B \(\frac{x}{a}+\frac{\mathrm{y}}{\mathrm{~b}}=1\)
  3. C \(a x+b y=1\)
  4. D \(x+y=a+b\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{x}{a}+\frac{\mathrm{y}}{\mathrm{~b}}=1\)

Step-by-step Solution

Detailed explanation

Point where curve crosses Y-axis: \(x=0 \implies y=b e^{-0/a} = b\). Point: \((0, b)\) Derivative: \(\frac{dy}{dx} = b e^{-x/a} \left(-\frac{1}{a}\right) = -\frac{b}{a} e^{-x/a}\)