MHT CET · Maths · Application of Derivatives
The equation of the tangent to the curve \(y=4 x e^{x}\) at \(\left(-1, \frac{-4}{e}\right)\) is
- A \(y=-1\)
- B \(y=-\frac{4}{e}\)
- C \(x=-1\)
- D \(x=\frac{-4}{e}\)
Answer & Solution
Correct Answer
(B) \(y=-\frac{4}{e}\)
Step-by-step Solution
Detailed explanation
Given curve is \(y=4 x e^{x}\) \(\frac{d y}{d x}=4 e^{x}+4 x e^{x}\)
At \(\left(-1,-\frac{4}{e}\right)\left(\frac{d y}{d x}\right)_{(-1,-4 / e)}=4 e^{-1}+4(-1) e^{-1}=0\)
\(\therefore\) Equation of tangent is
\(\left(y+\frac{4}{e}\right) =0(x+1)\)
\(\Rightarrow y =-\frac{4}{e}\)
At \(\left(-1,-\frac{4}{e}\right)\left(\frac{d y}{d x}\right)_{(-1,-4 / e)}=4 e^{-1}+4(-1) e^{-1}=0\)
\(\therefore\) Equation of tangent is
\(\left(y+\frac{4}{e}\right) =0(x+1)\)
\(\Rightarrow y =-\frac{4}{e}\)
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