MHT CET · Maths · Three Dimensional Geometry
The equation of the plane passing through the point \((2,2,1)\) and the intersection of the planes \(x+2 y-3 z+1=0\) and \(3 x-2 y+4 z+3=0\) is
- A \(3 x+26 y+43 z+3=0\)
- B \(3 x+26 y-43 z-3=0\)
- C \(3 x-26 y-43 z-3=0\)
- D \(3 x-26 y+43 z+3=0\)
Answer & Solution
Correct Answer
(D) \(3 x-26 y+43 z+3=0\)
Step-by-step Solution
Detailed explanation

But it passes through \((2,2,1)\)
\(\Rightarrow(2+2 \times 2-3 \times 1+1)+\lambda(3 \times 2-2 \times 2+4 \times 1+3)=0\)
\(\Rightarrow 4+9 \lambda=0\)
\(\Rightarrow \lambda=\frac{-4}{9} \text { in eq. (1) we get}\)
\(3 x-26 y+43 z+3=0\)
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