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MHT CET · Maths · Three Dimensional Geometry

The equation of the plane passing through the point -1,2,1 and perpendicular to the line joining the points -3,1,2 and 2,3,4 is ________

  1. A r-.5i^+2j^+2k^=1
  2. B r-.5i^+2j^+2k^=-1
  3. C r-.5i^-2j^+2k^=-5
  4. D r-.5i^-2j^-2k^=1
Verified Solution

Answer & Solution

Correct Answer

(A) r-.5i^+2j^+2k^=1

Step-by-step Solution

Detailed explanation

Since, direction ratio of normal
Are 2--3,3-1,4-2
= 5,2,2
Then, equation of plane is 5x+1+2y-2+2z-1=0
=5x+2y+2z-1=0
=r.¯5i+2j+2k=1
Or Equation of plane passing through
a¯=-i+2j-k and the position vector of normal n¯=5i+2j+2k
is r¯-a¯.n¯=0,r.¯5i+2j+2k=1