MHT CET · Maths · Three Dimensional Geometry
The equation of the plane containing the line \(\frac{x}{1}=\frac{y}{2}=\frac{z}{3}\) and perpendicular to the plane containing the lines \(\frac{x}{2}=\frac{y}{3}=\frac{z}{1}\) and \(\frac{x}{3}=\frac{y}{2}=\frac{z}{1}\) is
- A \(x-13 y+z=0\)
- B \(13 x-8 y+5 z=0\)
- C \(13 x-8 y+z=0\)
- D \(13 x-y+z=0\)
Answer & Solution
Correct Answer
(C) \(13 x-8 y+z=0\)
Step-by-step Solution
Detailed explanation
Direction vector of the first line is \(\vec{d_1} = \langle 1, 2, 3 \rangle\). Direction vectors of the two lines in the second plane are \(\vec{d_2} = \langle 2, 3, 1 \rangle\) and \(\vec{d_3} = \langle 3, 2, 1 \rangle\).
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