MHT CET · Maths · Parabola
The equation of the directrix of the parabola \(y^2+4 y+4 x+2=0\) is
- A \(x=-1\)
- B \(x=1\)
- C \(x=\frac{-3}{2}\)
- D \(x=\frac{3}{2}\)
Answer & Solution
Correct Answer
(D) \(x=\frac{3}{2}\)
Step-by-step Solution
Detailed explanation
\((y+2)^2 = -4(x-\frac{1}{2})\) \(h=\frac{1}{2}, 4a=4 \Rightarrow a=1\)
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