MHT CET · Maths · Parabola
The equation of the directrix of the parabola \(3 x^{2}=16 y\) is
- A \(3 y+4=0\)
- B \(3 x+4=0\)
- C \(3 y-4=0\)
- D \(3 x-4=0\)
Answer & Solution
Correct Answer
(A) \(3 y+4=0\)
Step-by-step Solution
Detailed explanation
\(3 x^{2}=16 y\)
\(x^{2}=\frac{16}{3} \quad ; a=\frac{4}{3}\)
Digectin \(\rightarrow\)
\(y+\frac{4}{3}=0\)
\(3 y+4=0\)
\(x^{2}=\frac{16}{3} \quad ; a=\frac{4}{3}\)
Digectin \(\rightarrow\)
\(y+\frac{4}{3}=0\)
\(3 y+4=0\)
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