MHT CET · Maths · Differential Equations
The equation of the curve passing through the origin and satisfying the equation \(\left(1+x^2\right) \frac{\mathrm{dy}}{\mathrm{d} x}+2 x y=4 x^2\), is
- A \(3\left(1+x^2\right) \mathrm{y}=4 x^3\)
- B \(3\left(1-x^2\right) \mathrm{y}=4 x^3\)
- C \(3\left(1+x^2\right)=x^3\)
- D \(4\left(1-x^2\right)=x^3\)
Answer & Solution
Correct Answer
(A) \(3\left(1+x^2\right) \mathrm{y}=4 x^3\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{dy}}{\mathrm{d} x} + \frac{2x}{1+x^2} y = \frac{4x^2}{1+x^2}\) IF \( = e^{\int \frac{2x}{1+x^2} \mathrm{d}x} = e^{\ln(1+x^2)} = 1+x^2\)
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