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MHT CET · Maths · Parabola

The equation of the common tangent touching the circle \((x-3)^{2}+y^{2}=9\) and the parabola \(y^{2}=4 x\) above the \(x\) -axis is

  1. A \(\sqrt{2} y=3 x+1\)
  2. B \(\sqrt{3} y=-(x+3)\)
  3. C \(\sqrt{3} y=x+3\)
  4. D \(\sqrt{3} y=-(3 x+1)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt{3} y=x+3\)

Step-by-step Solution

Detailed explanation

Let the common tangent to the parabola
\(
\begin{array}{l}
y^{2}=4 x \text { be } \\
y=m x+\frac{1}{m}
\end{array}
\)
It should be also touch the circle
\(
(x-3)^{2}+y^{2}=9
\)
whose centre is \((3,0)\) and radius \(=3\), then
\(
\begin{array}{cc}
& \frac{|3 m+1 / m|}{\sqrt{1+m^{2}}}=3 \\
\Rightarrow & 3 m^{2}=1 \\
\Rightarrow & \quad m=\pm \frac{1}{\sqrt{3}}
\end{array}
\)
But \(m>0\), then equation of common tangent is
\(
y=\frac{1}{\sqrt{3}} \cdot x+\sqrt{3}
\)
or \(\sqrt{3} \cdot y=x+3\)