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MHT CET · Maths · Application of Derivatives

The equation of tangent at \(\mathrm{P}(-4,-4)\) on the curve \(x^{2}=-4 y\) is

  1. A 2x+y+4=0
  2. B 2x-y+4=0
  3. C 2x+y-4=0
  4. D 3x-y+8=0
Verified Solution

Answer & Solution

Correct Answer

(B) 2x-y+4=0

Step-by-step Solution

Detailed explanation

(D)
We have \(x^{2}=-4 y \Rightarrow 2 x=-4 \frac{d y}{d x} \Rightarrow \frac{d y}{d x}=\frac{-x}{2}\)
Hence slope of tangent at \(P(-4,-4)\) is 2 . Hence required eq. of tangent is \(y+4=2(x+4) \quad \Rightarrow 2 x-y+4=0\)