MHT CET · Maths · Circle
The equation of circle with centre at \((2,-3)\) and the circumference \(10 \pi\) units is
- A \(x^2+y^2-4 x+6 y-12=0\)
- B \(x^2+y^2-4 x-6 y-12=0\)
- C \(x^2+y^2+4 x+6 y+12=0\)
- D \(x^2+y^2-4 x+6 y+12=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-4 x+6 y-12=0\)
Step-by-step Solution
Detailed explanation
We have \(2 \pi r=10 \pi \Rightarrow r=5\) and centre of circle is \((2,-3)\) Hence equation of circle is \((x-2)^2+(y+3)^2=(5)^2\) i.e. \(x^2+y^2-4 x+6 y-12=0\)
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