MHT CET · Maths · Circle
The equation of circle passing through the points \((1,-2)\) and \((4,-3)\) and whose centre lies on the line \(3 x+2 y=7\) is
- A \(x^2+y^2+6 x-2 y-5=0\)
- B \(x^2+y^2-6 x-2 y+5=0\)
- C \(x^2+y^2+6 x+2 y-5=0\)
- D \(x^2+y^2-6 x+2 y+5=0\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2-6 x+2 y+5=0\)
Step-by-step Solution
Detailed explanation
Let the equation of the required circle be \(x^2+y^2+2 g x+2 f y-C=0\)
from (iii) + (iv)
\(9 g=-27 \Rightarrow g=-3\)
then \(f=1\) and \(c=5\)
So, the required equation is \(x^2+y^2-6 x+2 y+5=0\)
from (iii) + (iv)
\(9 g=-27 \Rightarrow g=-3\)
then \(f=1\) and \(c=5\)
So, the required equation is \(x^2+y^2-6 x+2 y+5=0\)
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