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MHT CET · Maths · Three Dimensional Geometry

The equation of a plane containing the point \((1,-1,1)\) and parallel to the plane
\(2 x+3 y-4 z=17\) is

  1. A \(\bar{r}_{\cdot}(2 \hat{\imath}+3 \hat{\jmath}-4 \hat{k})=-5\)
  2. B \(\bar{r} \cdot(2 \hat{\imath}+3 \hat{\jmath}-4 \hat{k})=-15\)
  3. C \(\bar{r} \cdot(4 \hat{\imath}+3 \hat{\jmath}-4 \hat{k})=-3\)
  4. D \(\bar{r} \cdot(3 \hat{\imath}+4 \hat{\jmath}-2 \hat{k})=-3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\bar{r}_{\cdot}(2 \hat{\imath}+3 \hat{\jmath}-4 \hat{k})=-5\)

Step-by-step Solution

Detailed explanation

Equation of plane passing through the point having position vector \(\bar{a}\) and normal to \(\overline{\mathrm{n}}\) is
\(\therefore \overline{\mathrm{r}} \cdot \overline{\mathrm{n}} \cdot(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}})=(\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}}) \cdot(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}~-\) \(4 \hat{\mathrm{k}})=2-3-4=-5\)