MHT CET · Maths · Straight Lines
The equation of a line with slope \(-\frac{1}{\sqrt{2}}\) and makes an intercept of \(2 \sqrt{2}\) units on negative direction of \(y\)-axis is
- A \(\sqrt{2} y-x+4=0\)
- B \(x+\sqrt{2} y+2 \sqrt{2}=0\)
- C \(\sqrt{2} y+x+4=0\)
- D \(x+\sqrt{2} y-2 \sqrt{2}=0\)
Answer & Solution
Correct Answer
(C) \(\sqrt{2} y+x+4=0\)
Step-by-step Solution
Detailed explanation
The line passes through point \((0,-2 \sqrt{2})\) and has slope \(=\frac{-1}{\sqrt{2}}\) Hence equation of line is
\((\mathrm{y}+2 \sqrt{2})=\frac{-1}{\sqrt{2}}(\mathrm{x}-0) \Rightarrow \mathrm{x}+\sqrt{2} \mathrm{y}+4=0\)
\((\mathrm{y}+2 \sqrt{2})=\frac{-1}{\sqrt{2}}(\mathrm{x}-0) \Rightarrow \mathrm{x}+\sqrt{2} \mathrm{y}+4=0\)
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