MHT CET · Maths · Straight Lines
The equation of a line passing through the point of intersection of the lines \(-2 y+8=0\) and \(3 x-y+4=0\) and having \(x\) and \(y\) intercept zero is
- A \(4 x-5 y=0\)
- B \(5 x-4 y=0\)
- C \(5 x+4 y=0\)
- D \(4 x+5 y=0\)
Answer & Solution
Correct Answer
(A) \(4 x-5 y=0\)
Step-by-step Solution
Detailed explanation
\(
\begin{array}{l}
x+2 y+8=0 \\
3 x-y+4=0
\end{array}
\)
Solving we get; \(x=\frac{-16}{7} ; y=\frac{-20}{7}\)
line pacsing through \((0,0)\) & \(\left(\frac{-16}{7}, \frac{-20}{7}\right)\) & having \(x\) & \(y\) intercept \(5 x-4 y=0\)
\begin{array}{l}
x+2 y+8=0 \\
3 x-y+4=0
\end{array}
\)
Solving we get; \(x=\frac{-16}{7} ; y=\frac{-20}{7}\)
line pacsing through \((0,0)\) & \(\left(\frac{-16}{7}, \frac{-20}{7}\right)\) & having \(x\) & \(y\) intercept \(5 x-4 y=0\)
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