MHT CET · Maths · Straight Lines
The equation of a line passing through the point \((7,-4)\) and perpendicular to the
line passing through the points \((2,3)\) and \((1,-2)\) is
- A \(x+5 y+13=0\)
- B \(x-5 y-13=0\)
- C \(x-2 y-15=0\)
- D \(x+2 y+1=0\)
Answer & Solution
Correct Answer
(A) \(x+5 y+13=0\)
Step-by-step Solution
Detailed explanation
Slope of line through \((2,3)\) and \((1,-2)\) is \(\frac{-2-3}{1-2}=5\)
Hence slope of required line is \(-\frac{1}{5}\)
Equation of required line is
\((y+4)=-\frac{1}{5}(x-7) \Rightarrow 5 y+20=-x+7 \text { i.e. } x+5 y\)\(+13=0\)
Hence slope of required line is \(-\frac{1}{5}\)
Equation of required line is
\((y+4)=-\frac{1}{5}(x-7) \Rightarrow 5 y+20=-x+7 \text { i.e. } x+5 y\)\(+13=0\)
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