MHT CET · Maths · Three Dimensional Geometry
The equation of a line passing through the point ( \(-1,2,3\) ) and perpendicular to the lines \(\frac{x}{2}=\frac{y-1}{-3}=\frac{z+2}{-2}\) and \(\frac{x+3}{-1}=\frac{y+3}{2}=\frac{z-1}{3}\) is
- A \(\frac{x+1}{5}=\frac{y-2}{-4}=\frac{z+3}{1}\)
- B \(\frac{x+1}{5}=\frac{y+2}{4}=\frac{z+3}{1}\)
- C \(\frac{x+1}{5}=\frac{y-2}{4}=\frac{z-3}{-1}\)
- D \(\frac{x+1}{1}=\frac{y-2}{4}=\frac{z-3}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{x+1}{5}=\frac{y-2}{4}=\frac{z-3}{-1}\)
Step-by-step Solution
Detailed explanation
Direction vector of first line: \( \vec{d_1} = (2, -3, -2) \) Direction vector of second line: \( \vec{d_2} = (-1, 2, 3) \)
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