MHT CET · Maths · Straight Lines
The equation of a line passing through \((\rho \cos \propto, p \sin \propto)\) and making an angle \((90+\propto)\) with positive direction of \(\mathrm{X}\)-axis is
- A \(x \cos \propto-y \sin \propto=2 p\)
- B \(x \sin \propto+y \cos \propto=p\)
- C \(x \cos \propto+y \sin \propto=p\)
- D \(\mathrm{x} \cos \propto+\mathrm{y} \sin \propto=3 \mathrm{p}\)
Answer & Solution
Correct Answer
(C) \(x \cos \propto+y \sin \propto=p\)
Step-by-step Solution
Detailed explanation
Slope of line \(=\tan (90+\propto)=-\cot \propto\)
Equation of required line is
\(
\begin{aligned}
& (y-p \sin \propto)=\frac{-\cos \propto}{\sin \propto}(x-p \cos \propto) \\
& \therefore(\sin \propto) y-p \sin ^2 \propto=(-\cos \propto) x+p \cos ^2 \propto \\
& \therefore(\operatorname{Cos} \propto) x+(\sin \propto) y=p
\end{aligned}
\)
Equation of required line is
\(
\begin{aligned}
& (y-p \sin \propto)=\frac{-\cos \propto}{\sin \propto}(x-p \cos \propto) \\
& \therefore(\sin \propto) y-p \sin ^2 \propto=(-\cos \propto) x+p \cos ^2 \propto \\
& \therefore(\operatorname{Cos} \propto) x+(\sin \propto) y=p
\end{aligned}
\)
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