MHT CET · Maths · Functions
The domain of the function \(f(x)=\sqrt{x}\) is
- A \(R-\{0\}\)
- B \(R^{+}\)
- C \(\mathrm{R}^{+} \cup\{0\}\)
- D R
Answer & Solution
Correct Answer
(C) \(\mathrm{R}^{+} \cup\{0\}\)
Step-by-step Solution
Detailed explanation
(B)
For \(\mathrm{f}(\mathrm{x})\) to be defined, the term under the square root should be greater than or equal to zero.
\(x \geq 0\)
So domain is \([0, \infty]\) i.e. \(\mathrm{R}^{+} \cup\{0\}\).
For \(\mathrm{f}(\mathrm{x})\) to be defined, the term under the square root should be greater than or equal to zero.
\(x \geq 0\)
So domain is \([0, \infty]\) i.e. \(\mathrm{R}^{+} \cup\{0\}\).
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